Question

Tìm y, biết :

a) y+30%.y = -1,3

b)y-25%.y=1/2

Giải chi tiết ☺ ☺ ☺ ☻ ☻

Answer 1

a,y+30%y=-1,3

  y+3/10y=-1,3

y(1+3/10)=-1,3

y(10/10+3/10)=-1,3

13/10y=-13/10

y=-13/10:13/10

y=-1

Vậy y=-1

b,y-25%y=1/2

y-1/4y=1/2

y(1-1/4)=1/2

y(4/4-1/4)=1/2

3/4y=1/2

y=1/2:3/4

y=3/8

Vậy y=3/8

Answer 2

a/ y + 30%y = -1,3  

   => y + \(\frac{3}{10}\)y = -1,3

   => \(\frac{13}{10}\)y = -1,3

   => y = -1

b/ y - 25%.y = \(\frac{1}{2}\)

   => y - \(\frac{1}{4}\)y = \(\frac{1}{2}\)

   => \(\frac{3}{4}\)y = \(\frac{1}{2}\)  => y = \(\frac{2}{3}\)

Answer 3

a)\(y+30\%y=-1,3\)

\(y\frac{130}{100}=\left(-\frac{130}{100}\right)\)

\(y=\left(-\frac{130}{100}\right):\frac{130}{100}\)

\(y=-1\)

b)\(y-25\%y=\frac{1}{2}\)

\(y\frac{75}{100}=\frac{50}{100}\)

\(y=\frac{50}{100}:\frac{75}{100}\)

\(y=\frac{2}{3}\)