y=\(\frac{17}{10}\)
nếu đúng thì k
(\(\frac{9}{4}-y\))x \(\frac{5}{6}=\frac{1}{2}+\frac{1}{3}\)
(\(\frac{9}{4}-y\))x \(\frac{5}{6}=\frac{3}{6}+\frac{2}{6}\)
\(\left(\frac{9}{4}-y\right)x\frac{5}{6}=\frac{5}{6}\)
\(\frac{9}{4}-y=\frac{5}{6}:\frac{5}{6}\)
\(\frac{9}{4}-y=1\)
\(y=\frac{9}{4}-1\)
\(y=\frac{9}{4}-\frac{4}{4}\)
\(y=\frac{5}{4}\)
9/4-yx5/6=1/2+1/3
9/4-yx5/6=5/6
yx5/6=9/4-5/6
yx5/6=17/12
y=17/12:5/6
y=17/12x6/5
y=17/10