Ta có: \(71+\left(65\times4\right)=\frac{y+140}{y+260}\)
\(\Leftrightarrow331=\frac{y+140}{y+260}\)
\(\Leftrightarrow331\left(y+260\right)=y+140\)
\(\Leftrightarrow331y+86060=y+140\)
\(\Leftrightarrow331y-y=140-86060\)
\(\Leftrightarrow330y=-85920\)
\(\Leftrightarrow y=\frac{-85920}{330}=\frac{-2864}{11}\)
71+65*4 =y+140/y+260
tìm y :
a/ y + y : 3 x 4.5 + y : 2 x 76 = 24
b / 71 + 65 x 4 = y + 140 : y + 260
Bài 3 : Tìm y ,x
a) 71 + 65 x 4 = \(\frac{X+140}{X}+260\)
b) y x 15/2 - 1/3 x ( 1/4 + y ) = \(96\frac{2}{3}\)
tìm X
71 + 65 x 4 = X + 140 / X +260
1.Tìm x biết:
71 + 65*4=x + 140 / x + 260
2.Tính
A = 6666666666 * 3333333333
e) y x 9,2 + y : 0,25 - y x 3,2 = \(\frac{3}{4}x\left(1\frac{1}{2}-\frac{6}{8}\right)\) g) 71 + 65 x 4 = \(\frac{X+140}{X}+260\)
71+65×4=(x+140)÷x+260
Tìm x
71 + 65 x 4 = \(\frac{x+140}{x}+260\)
71 + 65 x 4 = x + 140 / x + 260.
