ta có \(x:y:z=3:5:\left(-2\right)\)và\(5x-y-3z=2\)
\(=>\frac{x}{3}=\frac{y}{5}=\frac{-z}{2}\)=>\(\frac{5x}{15}=\frac{y}{5}=-\frac{3z}{6}\)
áp dụng tính chất dãy tỉ số bằng nhau ta có
\(\frac{5x}{15}=\frac{y}{5}=-\frac{3z}{6}=\frac{5x-y+\left(-3z\right)}{15-5+6}=\frac{5x-y-3z}{16}=\frac{2}{16}=\frac{1}{8}\)
*\(\frac{x}{3}=\frac{1}{8}=>x=\frac{1}{8}.3=\frac{3}{8}\)
*\(\frac{y}{5}=\frac{1}{8}=>y=\frac{1}{8}.5=\frac{5}{8}\)
*\(-\frac{z}{2}=\frac{1}{8}=>z=\frac{1}{8}.\left(-2\right)=-\frac{1}{4}\)
vậy \(x=\frac{3}{8};y=\frac{5}{8};z=-\frac{1}{4}\)