Question

Tìm x,y,z

(3x-5)²⁰¹⁰+(y-1)²⁰¹²+(x-z)²⁰¹⁴=0

Answer 1

Ta có \(\left(3x-5\right)^{2010}+\left(y-1\right)^{2012}+\left(x-z\right)^{2014}=0\left(1\right)\)

Vì \(2010;2012;2014\) đều là số mủ chẵn (2)

Từ (1) và (2) 

\(\Rightarrow\left(3x-5\right)=0;\left(y-1\right)=0;\left(x-z\right)=0\)

\(\left(+\right)3x-5=0\Rightarrow3x=5\Rightarrow x=\frac{5}{3}\)

\(\left(+\right)y-1=0\Rightarrow y=1\)

\(\left(+\right)x-z=0\Rightarrow z=x=\frac{5}{3}\)

Vậy \(x=z=\frac{5}{3};y=1\)