Áp dụng tc dãy tỉ số bằng nhau ta có :
x+y+z = x/y+z-2 = y/z+x-3 = z/x+y+5 = x+y+z/y+z-2+z+x-3+x+y+5 = 1/2
=> x+y+z = 1/2 = x = 1/2.(y+z-2) ; y = 1/2.(z+x-3) ; z = 1/2.(x+y+5)
Đến đó bạn tự giải nha
Tk mk nha
Tìm x,y,z nếu
\(x+y+z=\frac{x}{y+z-2}=\frac{y}{z+x-3}=\frac{z}{x+y+5}\)
Tìm x , y , z nếu :
a)\(\frac{x+y+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
b)\(\frac{x-1}{2}=\frac{y-2}{3}=\frac{z-3}{4}\)và 2x+3y-z=50
Tìm x,y,z \(\frac{y+z+3}{x}=\frac{x+z+2}{y}=\frac{x+y-5}{z}=\frac{1}{x+y+z}\)
Tìm x,y,z biết
\(x+y+z=\frac{x}{y+z-2}=\frac{y}{z+x-3}=\frac{z}{x+y+5}\)
tìm x , y , z biết : \(\frac{x}{x+z-5}=\frac{y}{x+z+3}=\frac{z}{x+y+2}=\frac{1}{2}\left(x+y+z\right)\)
Tìm x, y, z biết: \(\frac{x}{y+z-5}=\frac{y}{x+z+3}=\frac{z}{x+y+2}=\frac{1}{2}\left(x+y+z\right)\)
Tìm x,y,z biết:
\(\frac{x+y+3}{z}=\frac{y+z-5}{x}=\frac{x+z+2}{y}=2\left(x+y+z\right)\)
Tìm x,y,z biết \(x+y+z=\frac{x}{y+z-2}=\frac{y}{z+x-3}=\frac{z}{x+y+5}\)
a) \(\frac{y+z+1}{x}=\frac{x+z+2}{y}=\frac{x+y-3}{z}=\frac{1}{x+y+z}\)
b) \(\frac{x}{y+z+1}=\frac{y}{x+z+2}=\frac{z}{x+y-2}=x+y+z\)
Tìm x ;y;z
