Question

Tìm x,y,z biết:

\(\frac{x}{5}=\frac{x+y}{8}=\frac{x+y-2z}{4}=3\)

Answer 1

Từ \(\frac{x}{5}=3\Rightarrow x=15\)

\(\frac{15+y}{8}=3\Rightarrow y=9\)

\(\frac{15+9-2z}{4}=3\Rightarrow z=6\)

Answer 2

chắc ko

Answer 3

\(\frac{x}{5}\)=3=\(\frac{15}{5}\)=>x=15

\(\frac{x+y}{8}\)=3=\(\frac{24}{8}\)=>x+y=24 =>15+y=24=>y=9

\(\frac{x+y-2z}{4}\)=3=\(\frac{12}{4}\)=>x+y-2z=12=>15+9-2z=12=>24-2z=12=>2z=24-12=12

=>z=6

vậy các số x,y,z=15,9,6