\(3x=4y\Rightarrow\frac{x}{4}=\frac{y}{3}\left(1\right)\)
\(4y=5z\Rightarrow\frac{y}{5}=\frac{z}{4}\left(2\right)\)
Từ (1) và (2) => \(\frac{x}{20}=\frac{y}{15}=\frac{z}{12}\).
Theo t/c dãy tỉ số = nhau:
\(\frac{x}{20}=\frac{y}{15}=\frac{z}{12}=\frac{x-\left(y+z\right)}{20-\left(15+12\right)}=\frac{-21}{-7}=3\)
\(\Rightarrow\frac{x}{20}=3\Rightarrow x=3.20=60\)
\(\Rightarrow\frac{y}{15}=3\Rightarrow y=3.15=45\)
\(\Rightarrow\frac{z}{12}=3\Rightarrow z=3.12=36\)
Vậy x=60; y=45; z=36.
x - (y + z) = -21 nên x - y - z = -21
\(3x=4y=5z\Rightarrow\frac{x}{\frac{1}{3}}=\frac{y}{\frac{1}{4}}=\frac{z}{\frac{1}{5}}\)
Áp dụng tính chất dãy tỉ số bằng nhau , ta có:
\(\frac{x}{\frac{1}{3}}=\frac{y}{\frac{1}{4}}=\frac{z}{\frac{1}{5}}=\frac{x-y-z}{\frac{1}{3}-\frac{1}{4}-\frac{1}{5}}=\frac{-21}{-\frac{7}{60}}=180\)
=> x = 180 . 1/3 = 60
=> y = 180 . 1/4 = 45
=> z = 180 . 1/5 = 36
