Question

tim x,y,z biet : x/2=y/3=z/5 va x-2y+z=10

Answer 1

Từ \(\frac{x}{2}=\frac{y}{3}=\frac{z}{5}\Rightarrow\frac{x}{2}=\frac{2y}{6}=\frac{z}{5}\)

Theo t/c dãy tỉ số=nhau:

\(\frac{x}{2}=\frac{2y}{6}=\frac{z}{5}=\frac{x-2y+z}{2-6+5}=\frac{10}{1}=10\)

+)x/2=10=>x=20

+)2y/6=10=>2y=60=>y=30

+)z/5=10=>z=50

Vậy................

Answer 2

\(\frac{x}{2}=\frac{y}{3}=\frac{z}{5}=\frac{2y}{6}=\frac{x-2y+z}{2-6+5}=10\)

\(\Rightarrow x=20\)       \(y=30\)            \(z=50\)