\(\frac{x+2}{7}=\frac{y-3}{5}=\frac{z}{3}=\frac{x+2+y-3-z}{7+5-3}=\frac{x+y-z-1}{9}=\frac{-17-1}{9}=\frac{-18}{9}=-2\)
\(\frac{x+2}{7}=-2\Rightarrow x=-16\)
\(\frac{y-3}{5}=-2\Rightarrow y=-12\)
\(\frac{z}{3}=-2\Rightarrow z=-6\)
Tim x,y,z biet:
(2|x|+5)/3=(3|y|-1)/5=(3-z)/7 va 2|x|+7|y|+3z=-14
tim x;y;z biet x/3=y/4;y/5=z/7 va x+y+z=98
Tim cac so x,y,z biet \(\frac{x}{5}=\frac{y}{7}=\frac{z}{3}\)va x2 va y2 va z2
Tim cac so x,y,z biet x/y=9/7; y/2=7/3 va x-y+z=-15
TIM X , Y , Z BIET
a x/3 = y/4 = z/5 va x + y + z = 36
b x/3 = y/4 = z/7 va 2x + y - z = - 24
tim x, y, z biet:
2/3.x=3/4.y=4/5.z va x+y-z=57
Tim x,y,z biet:
x+1/ 3 = y+2/ 4 = z+3/ 5 va x+y+z= 18
tim x,y,z biet : x/2=y/3=z/5 va x-2y+z=10
Tim x,z,y biet
x/2=y/3;y/4=z/5 va x+y-z=10
