z đâu ra vậy?
\(x-y=x\div y=2\left(x-y\right)\)
\(\left(x-y\right)=2\left(x-y\right)\Rightarrow x-y=0\Rightarrow x=y\)
mà \(\frac{x}{y}=x-y=0\Rightarrow x=0\Rightarrow y=0\left(ktm\right)\)
vậy ko có cặp số x, y thỏa mãn điều kiện bài toán
Tim x, y biet: x+y=x:y=3(x-y)
Tim x, y biet: x+y=x:y=3(x-y)
Tim cac so x;yb biet x+y=.x. y=x:y
Tim so huu ti x,y biet rang x-y bang x:y va bang 3 lan x+y
Tim hai so huu ti x, y( y khac 0), biet
x-y= x.y= x:y
tim hai so huu ti x va y(y khac 0) biet rang :
x-y=x.y=x:y
tim x,y,z biet; x/z+y+1=y/x+z+1=x+y-2=x+y+z
tim x,y,z biet y+z+1=x+z+2/y=x+y-3/2=1/x+y+z
tim x;y;z biet x(x+y+z)=2; y(x+y+z)=25; z(x+y+z)=-2; x>0
