Question

Tìm x,y,z biết: (x-y^2 + z)^2 + (y-2)^2 +(z+3)^2 = 0

Answer 1

\(\Rightarrow\)x-y^2+z=0

        y-2=0

        z+3=0

\(\Rightarrow\)\(\hept{\begin{cases}x-4-3=0\\y=2\\z=-3\end{cases}}\)x=7