Question

Tìm x,y.z biết (x-2016)^2016+(y-2017)^2018 +/x-y+z/=0

Answer 1

vì (x-2016)^2016 >= 0 vs mọi x

    (y-2017)^2018>= 0 vs mọi y

    /x+y-z/ >= 0 vs mọi x,y,z

mà (x-2016)^2016+(y-2017)^2018+/x-y+z/=\(\hept{\begin{cases}\left(x-2016\right)^{2016}=0\\^{\left(-2017\right)^{2018}}=0\\x+y-z=0\end{cases}}\)0 nên ​^{_{\(\hept{\begin{cases}x-2016=0\\y-2017=0\\x+y-z\end{cases}}\)\(\hept{\begin{cases}x=2016\\y=2017\\x+y-z=0\end{cases}}\)}}

Answer 2

mà x+y=2016+2017=4033

\(\Rightarrow\)4033-z=0

z=4033

vậy x=2016 y=2017 z=4033