Có \(2x=3y;5y=7z\) Suy ra \(5.2x=5.3y;3.5y=3.7z\)
\(\Rightarrow2.5.x=3.5.y=3.7.z\)
Chia các vế cho 2.3.5.7 ta được: \(\frac{x}{3.7}=\frac{y}{2.7}=\frac{z}{2.5}\)
\(\Rightarrow\frac{x}{21}=\frac{y}{14}=\frac{z}{10}\)
\(\Rightarrow\frac{x}{21}=\frac{5x}{5.21}=\frac{y}{14}=\frac{7y}{7.14}=\frac{z}{10}=\frac{5z}{5.10}\)
\(\Rightarrow\frac{x}{21}=\frac{5x}{105}=\frac{y}{14}=\frac{7y}{98}=\frac{z}{10}=\frac{5z}{50}=\frac{5x-7y+5z}{105-98+50}=\frac{30}{57}\)
\(\Rightarrow x=21.\frac{30}{37}\); \(y=14.\frac{30}{57}\); \(z=10.\frac{30}{57}\)
Ta co : 2x=3y;5y=7z va 5x-7y+5z=30
\(2x=3y\Rightarrow\frac{x}{3}=\frac{y}{2};5y=7z\Rightarrow\frac{y}{7}=\frac{z}{5}\)
\(\frac{x}{3}=\frac{y}{2};\frac{y}{7}=\frac{z}{5}\Rightarrow\frac{x}{3}=\frac{7y}{14};\frac{2y}{14}=\frac{z}{5}\Rightarrow\frac{x}{21}=\frac{y}{14}=\frac{z}{10}\Rightarrow\frac{5x}{105}=\frac{7y}{98}=\frac{5z}{50}\)
Ap dung tinh chat day ti so bang nhau ta co :
\(\frac{5x}{105}=\frac{7y}{98}=\frac{5z}{50}=\frac{5x-7y+5z}{105-98+50}=\frac{30}{57}=?\)
1/ Ta có xy=-6
Với x=-6 => y=1
x=-3 => y=2
x= -2 => y=3
x=-1 => y=6
2/ Ta có x=y+4
Thay x=y+4 vào bt, ta được
<=> y+4-3/y-2 =3/2
<=> y+1/y-2=3/2
<=> 2(y+1)=3(y-2)
<=> 2y +2 = 3y - 6
<=> 3y - 2y= 2+ 6
<=> y= 8 <=> x= 12
3/ -4/8 = x/-10 <=> x= (-4)*(-10)/8=5
-4/8 = -7/y <=> y=(-7)*8/(-4) =14
-4/8 = z/-24 <=> z= (-4)*(-24)/8=12
Áp dụng tính chất dãy tỉ số bằng nhau
\(\frac{x}{5}=\frac{y}{7}=\frac{z}{9}=\frac{x-y+z}{5-7+9}=\frac{315}{7}=45\)
suy ra: x/5 = 45 => x = 225
y/7 = 45 => y = 315
z/9 = 45 => z = 405
Từ : 2x = 3y => \(\frac{x}{3}=\frac{y}{2}\Rightarrow\frac{x}{21}=\frac{y}{14}\)
5y = 7z => \(\frac{y}{7}=\frac{z}{5}\Rightarrow\frac{y}{14}=\frac{z}{10}\)
\(\Rightarrow\frac{x}{21}=\frac{y}{14}=\frac{z}{10}\)
Ta có :
\(\frac{x}{21}=\frac{y}{14}=\frac{z}{10}=\frac{5x-7y+5z}{105-98+50}=\frac{30}{57}=\frac{10}{19}\)
\(\Rightarrow\hept{\begin{cases}\frac{x}{21}=\frac{10}{19}\\\frac{y}{14}=\frac{10}{19}\\\frac{z}{10}=\frac{10}{19}\end{cases}}\Rightarrow\hept{\begin{cases}x=11,05263158\\y=7,368421053\\z=5,263157895\end{cases}}\)