Các câu hỏi tương tự
cho x>0,y>0, x+y=2012.
a, tim GTLN cua A= (2x^2+8xy+2y^2)/ (x^2+2xy+y^2)
b, tim GTNN cua B=(1+(2012/x))^2+(1+(2012/y))^2
tim x,y: x^2+y^2-2*x+4*y+5=0
giup tui giai bai toan nay voi
tim GTNN cua P= x^2/y^2+y^2/x^2-3(x/y+y/x)+5 (x#0;y#0)
tim x y z biết
a,4x^2+9y^2+4x-24y+17=0
b,2x^2+2y^2+z^2+2xy-2xz-6y+9=0
c,x^2+2y+2xy+2x+6y+5=0
cho x+y+4=0
Tim max B=2(x^3+y^3)+3(x^2+y^2)+10xy
1.thanh hieu hai binh phuong a)(x+y+4)*(x+y-4) b)(x-y+6)*(x+y-6) c)(y+2z-3)*(y-2z-3) d)(x+2y+3z)*(2y+3z-x)
2.rut gon a)(x+1)^2-(x-1)^2-3(x+1)*(x-1) b) 5(x+2)*(x-2)-1/2(6-8x)^2+17
3.tim x a)25x^2-9=0 b) (x+4)-(x+1(x-1)=16
tim x, y , z biet x^2 - xy + y^2=0
tim x,y,z biết
a)(2x-3)^2=0
b) 25x^2-10x+1=0
c) 6x+9=-x^2
d) 169-y^2=0
e) 2x^2-2xy-4x+5=0
giup mik vs
tôi đi hok
nhanh nhé
Chox,y,z>0,x+y+Z=2.Tim GTNN cua P=\(\frac{x^2}{y+z}+\frac{y^2}{x+z}+\frac{z^2}{x+y}\)