bai 1 Tim x,y
a, (x-3)x+3 =(x-3)x+13
b,\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-4y-7}{4x}\)
c,|x+5|=(3y-4)2016
bai 1 Tìm x,y \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-4y-7}{4x}\)
tìm x,y biết:
a \(\left(x-7\right)^{x+1}-\left(x-7\right)^{x+11}=0\)
b \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y-7}{4x}\)
c \(\left|x+5\right|+\left(3y-4\right)^{2010}=0\)
Tìm x, biết:\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-7y-7}{4x}\)
tìm x,y biết : \(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x-7y-7}{4x}\)
Tìm x, y biết :
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y}{4x}\)= 7
tim x;y
\(\frac{5x-1}{3}=\frac{7y-6}{5}=\frac{5x+7y-7}{4x}\)
Tìm cặp số x,y
a) \(\frac{2x+1}{5}=\frac{4y-2}{7}=\frac{2x+4y-1}{6x}\)
b) \(\frac{1+2x}{15}=\frac{7-3x}{20}=\frac{3y}{23+7x}\)
c) \(\frac{1+3y}{12}=\frac{1+5y}{5x}=\frac{1+7y}{4x}\)
\(\frac{5x-1}{3}\)= \(\frac{7y-6}{5}\)= \(\frac{5x-7y-7}{4x}\).Tìm x,y