Question

tìm x,y, z,t biết : 

\(\frac{x}{-3}\)=  \(\frac{y.1}{6}\)=\(\frac{2}{2}\)=\(\frac{t+1}{3}\)=\(\frac{8}{3}\)

Answer 1

Theo đề bài \(\Rightarrow\frac{x}{-3}=\frac{2}{2}\Rightarrow2x=2.\left(-3\right)\Rightarrow2x=-6\Rightarrow x=-3\)

\(\frac{y}{6}=\frac{2}{2}\Rightarrow2y=2.6\Rightarrow2y=12\Rightarrow y=6\)

\(\frac{t+1}{3}=\frac{8}{3}\Rightarrow3\left(t+1\right)=8.3\Rightarrow3t+3=24\Rightarrow3t=21\Rightarrow t=7\)

Vậy x = -3 ; y = 6 và t = 7

Answer 2

\(\frac{x}{-3}=\frac{y.1}{6}=\frac{2}{2}=\frac{t+1}{3}=\frac{8}{3}\)

=> \(\frac{x}{-3}=\frac{y}{6}=\frac{2}{2}=\frac{t+1}{3}=\frac{8}{3}\)

=> 2x = - 3 . 2

2x = -6

x = - 6 : 2

x = - 3 

2y = 6 . 2

y = \(\frac{6.2}{2}\)

y = 6

Vì \(\frac{t+1}{3}=\frac{8}{3}\)=> t + 1 = 8 => t = 7

Vậy x = 2 ; y = 6 ; t = 7