Để y có giá trị nguyên => \(x+3⋮x-2\)
Mà \(x-2⋮x-2\)
\(\Rightarrow\left(x+3\right)-\left(x-2\right)⋮x-2\)
\(\Rightarrow5⋮x-2\)
\(\Rightarrow x-2\inƯ\left(5\right)\)
\(Ư\left(5\right)=\left\{\pm1;\pm5\right\}\)
\(\Rightarrow x-2\in\left\{\pm1;\pm5\right\}\)
\(\Rightarrow x\in\left\{3;1;7;-3\right\}\)
\(\Rightarrow y\in\left\{6;-4;2;0\right\}\)