=) ta có x2 = 15+y2
đoán mò =) ta có
x=4
y=1
=) ta có x2 = 15+y2
đoán mò =) ta có
x=4
y=1
cau 1,(n^2-7)\(⋮\)n+3
cau 2 tim x;y;z
bietx-y=-9
y-z=-10
z+x=11
Tim x, y thuoc Z biet : | x-2| + (x-y+1)^2 =0
tim x,y thuoc z biet
-24/-6 = x/3 = 4/y^2 = z^3/-2
tim x,y,z thuoc Z biet /2x-4/+/y+2/+/2x+3y-z/=0
tim x, y thuoc Z:
2/x=y/3
tim x,y,z thuoc N sao cho 1/x+1/y+1/z=1/2
tim x,y thuoc z biet (x-2).(y+12)<0
tim x y thuoc z biết | x -1| + |y | = 2
( x -1) mu 2 + y mu 2 = 4
x/y = 2/7
tim x y thuoc Z