\(\frac{5}{x}+\frac{y}{4}=\frac{1}{8}\)
\(\frac{5}{x}=\frac{1}{8}-\frac{y}{4}\)
\(\frac{5}{x}=\frac{1-2y}{8}\)
\(\Rightarrow5.8=x.\left(1-2y\right)\)
\(\Rightarrow40=x.\left(1-2y\right)\)
Vì 1-2y là số lẻ nên \(1-2y\in\left\{1;5;-1;-5\right\}\)
Ta có bảng:
1-2y | 1 | 5 | -1 | -5 |
2y | 0 | -4 | 2 | -6 |
y | 0 | -2 | 1 | -3 |
x | 40 | 8 | -40 | -8 |