a) \(x-2xy-3y+1=0\)
\(\Leftrightarrow x-y\left(2x-3\right)+1=0\)
\(\Leftrightarrow2x-2y\left(2x-3\right)+2=0\)
\(\Leftrightarrow2x-2y\left(2x-3\right)-3+5=0\)
\(\Leftrightarrow-2y\left(2x-3\right)+\left(2x-3\right)=-5\)
\(\Leftrightarrow\left(2x-3\right)\left(1-2y\right)=-5\)
tự tìm nốt
b) \(x-2xy+y=0\)
\(\Leftrightarrow x\left(1-2y\right)+y=0\)
\(\Leftrightarrow-2x\left(1-2y\right)-2y=0\)
\(\Leftrightarrow-2x\left(1-2y\right)-2y+1=1\)
\(\Leftrightarrow-2x\left(1-2y\right)+\left(1-2y\right)=1\)
\(\Leftrightarrow\left(1-2y\right)\left(1-2x\right)=1\)
Tìm nốt
a) \(x-2xy-3y+1=0\)
=> \(2\left(x-2xy-3y+1\right)=0\)
=> \(2x-4xy-6y+2=0\)
=> \(2x\left(1-2y\right)+3\left(1-2y\right)-1=0\)
=> \(\left(2x-3\right)\left(1-2y\right)=1\)
=> \(2x-3;1-2y\inƯ\left(1\right)=\left\{1;-1\right\}\)
Lập bảng :
| 2x - 3 | 1 | -1 |
| 1- 2y | 1 | -1 |
| x | 2 | 1 |
| y | 0 | 1 |
Vậy ...
b) t/t
