\(\frac{x-1}{3}+\frac{1}{y}=\frac{-1}{6}\)
\(\frac{\left(x-1\right)y}{3y}+\frac{3}{3y}=\frac{-1}{6}\)
\(\frac{\left(x-1\right)y+3}{3y}=\frac{-1}{6}\)
\(\frac{\left(x-1\right)y}{y}=\frac{\left(-1\right)-3}{6:3}\)
\(x-1=-2\)
\(x=\left(-2\right)+1\)
\(x=-1\)
\(\frac{x-1}{3}+\frac{1}{y}=\frac{-1}{6}\)
\(\frac{\left(x-1\right)y}{3y}+\frac{3}{3y}=\frac{-1}{6}\)
\(\frac{\left(x-1\right)y+3}{3y}=\frac{-1}{6}\)
\(x-1=\frac{\left(-1\right)-3}{6:3}\)
\(x-1=-2\)
\(x=\left(-2\right)+1\)
\(x=-1\)
bạn ơi câu thứ hai chưa làm
câu thứ 2 đây nha phanthilan:
\(\frac{x-1}{3}+\frac{1}{y-2}=\frac{-3}{4}\)
\(\frac{x}{3}-\frac{1}{3}+\frac{1}{y-2}=\frac{-3}{4}\)
\(\frac{x}{3}+\frac{1}{y-2}-\frac{1}{3}=\frac{-3}{4}\)
\(\frac{x}{3}+\frac{1}{y-2}=\frac{-3}{4}+\frac{1}{3}\)
\(\frac{x}{3}+\frac{1}{y-2}=\frac{-5}{12}\)
\(\frac{x\left(y-2\right)}{3\left(y-2\right)}+\frac{3}{3\left(y-2\right)}=\frac{-5}{12}\)
\(\frac{x\left(y-2\right)+3}{3\left(y-2\right)}=-\frac{5}{12}\)\(\)
còn lại tự bn suy nghĩ nha,mình vội lắm