Question

Tìm x,y \(\in\)Z thỏa mã:

a. \(\frac{1}{x}+\frac{y}{6}=\frac{1}{2}\)

b.\(\frac{x}{2}-\frac{2}{y}=\frac{1}{5}\)

c.\(\frac{x-1}{9}+\frac{1}{3}=\frac{1}{y+2}\)

d.\(\frac{x}{3}-\frac{4}{y}=\frac{1}{5}\)

Giup mk vs mk cần gấp câu trả lời 

Answer 1

a) \(\frac{1}{x}+\frac{y}{6}=\frac{1}{2}\)

\(\frac{1}{x}=\frac{1}{2}-\frac{y}{6}\)

\(\frac{1}{x}=\frac{3}{6}-\frac{y}{6}\)

\(\frac{1}{x}=\frac{3-y}{6}\)

\(\Rightarrow6=x.\left(3-y\right)\)

Lập bảng ta có :

3-y	2	3	-2	-3	1	6	-1	-6
x	3	2	-3	-2	6	1	-6	-1
y	1	0	5	6	2	-3	4	9

Vậy ...

b) tương tự câu a

c) \(\frac{x-1}{9}+\frac{1}{3}=\frac{1}{y+2}\)

\(\frac{x-1}{9}+\frac{3}{9}=\frac{1}{y+2}\)

\(\frac{x+2}{9}=\frac{1}{y+2}\)

\(\Rightarrow\left(x+2\right).\left(y+2\right)=9\)

x+2	3	-3	1	9	-1	-9
y+2	3	-3	9	1	-9	-1
x	1	-5	-1	7	-3	-11
y	1	-5	7	-1	-11	-3

Vậy ...

d) \(\frac{x}{3}-\frac{4}{y}=\frac{1}{5}\)

\(\frac{4}{y}=\frac{x}{3}-\frac{1}{5}\)

\(\frac{4}{y}=\frac{5x}{15}-\frac{3}{15}\)

\(\frac{4}{y}=\frac{5x-3}{15}\)

\(\Rightarrow4.15=y.\left(5x-3\right)\)

\(\Rightarrow60=y.\left(5x-3\right)\)

Lập bảng ta có :

nhiều tự làm