Question

Tìm x,y bt:

a) (2x - 3)¹⁵ = (2x - 3)⁷

b) (x-3)¹⁶ + (3y - 5)⁴= 0

Answer 1

a) (2x-3)¹⁵ = (2x-3)⁷

=> (2x-3)¹⁵ - (2x-3)⁷ = 0

(2x-3)⁷.[(2x-3)⁸ -1] = 0

=> (2x-3)⁷ = 0 => 2x-3 = 0 => 2x = 3 => x = 3/2

(2x-3)⁸ - 1 = 0 => (2x-3)⁸ = 1 => 2x - 3 = 1 => 2x = 4 => x = 2

                                              => 2x - 3 = - 1 => 2x = 2 => x = 1

KL:...

Answer 2

b) ta có: \(\left(x-3\right)^{16}\ge0;\left(3y-5\right)^4\ge0.\)

Để (x-3)¹⁶ + (3y-5)⁴ = 0

=> (x-3)¹⁶ = 0 => x-3 = 0 => x = 3

(3y-5)⁴ = 0 => 3y - 5 = 0 => 3y = 5 => y = 5/3

KL:...