Question

Tìm x,y biết:

\(x^2+\left(y-\frac{1}{10}\right)^4=0\)

Answer 1

\(x^2+\left(y-\frac{1}{10}\right)^4=0\)

\(\Rightarrow\hept{\begin{cases}x=0\\y-\frac{1}{10}=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\y=\frac{1}{10}\end{cases}}}\)

Answer 2

\(x^2+\left(y-\frac{1}{10}\right)^4=0\)

\(\Rightarrow\hept{\begin{cases}x^2=0\\y-\frac{1}{10}=0\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}x=0\\y=\frac{1}{10}\end{cases}}\)

Answer 3

huong pham:

\(x^2+\left(y-\frac{1}{10}\right)^4=0\)

\(\Rightarrow\orbr{\begin{cases}x^2=0\\y-\frac{1}{10}=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=0\\y=\frac{1}{10}\end{cases}}\)

Vậy x = 0 và y = 1/10

Tham khảo nha!