=> \(\frac{x-3}{3}=\frac{y-2}{2}\)
=> \(\frac{x-3}{3}+1=\frac{y-2}{2}+1\)
=> \(\frac{x}{3}=\frac{y}{2}=\frac{x-y}{3-2}=\frac{4}{1}=4\)
=> x = 4.3 =12
=> y = 4.2 = 8
\(\frac{x-3}{y-2}=\frac{3}{2}\)
=>\(\frac{x-3}{3}=\frac{y-2}{2}\)
=>\(\frac{x}{3}-1=\frac{y}{2}-1\)
=>\(\frac{x}{3}=\frac{y}{2}\)
=>2x=3y
Xét x-y =4
=>2x-2y=8
=>3y-2y=8
=>5y=8
=>y=8/5
=>y=1,6=>x=5,6
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