Question

tìm x,y biết 

a)   I x+2 I+I 3y-1 l=0

b)  I 3x-4 l+l3y-5l=0

Answer 1

a) Ta có:

\(\left|x+2\right|+\left|3y-1\right|=0\)

=> \(\left|x+2\right|=0\)và \(\left|3y-1\right|=0\)

Với \(\left|x+2\right|=0\)=> \(x+2=0\)=> \(x=-2\)

Với \(\left|3y-1\right|=0\)=> \(3y-1=0\)=> \(3y=1\)=>\(y=\frac{1}{3}\)

Vậy \(x=-2;y=\frac{1}{3}\)

b) Ta có:

\(\left|3x-4\right|+\left|3y-5\right|=0\)

=> \(\left|3x-4\right|=0\)và \(\left|3y-5\right|=0\)

Với \(\left|3x-4\right|=0\)=> \(3x-4=0\)=> \(3x=4\)=> \(x=\frac{4}{3}\)

Với \(\left|3y-5\right|=0\)=> \(3y-5=0\)=> \(3y=5\)=> \(y=\frac{5}{3}\)

Vậy \(x=\frac{4}{3};y=\frac{5}{3}\)