Đề như vầy mới đúng chứ : xy - 3x + 7y = 21
=> x(y - 3) + 7y = 21
=> x(y - 3) + 7y - 21 = 0
=> x(y - 3) + 7(y - 3) = 0
=> (y - 3) ( x + 7) = 0
\(\Leftrightarrow\hept{\begin{cases}y-3=0\\x+7=0\end{cases}}\)
\(\Leftrightarrow\hept{\begin{cases}y=3\\x=-7\end{cases}}\)
\(=> x.(y - 3) + 7y =21 \)
\(=> x. (y - 3) + 7y - 21 = 0\)
\(=> x.(y - 3) + 7(y - 3)= 0\)
\(=> (y - 3). (x + 7)= 0\)
Ta có : xy - 3x + 7y = 21
=> x(y - 3) + 7y = 21
=> x(y - 3) + 7y - 21 = 0
=> x(y - 3) + 7(y - 3) = 0
=> (y - 3) ( x + 7) = 0
<=> y − 3 = 0
x + 7 = 0
<=> y = 3
x = −7