\(x+\frac{1}{3}=\frac{4}{3}\)
\(x=\frac{4}{3}-\frac{1}{3}\)
\(x=\frac{3}{3}=1\)
k mình nhaMinh Hiền
\(x+\frac{1}{3}=\frac{4}{3}\)
\(x=\frac{4}{3}-\frac{1}{3}\)
\(x=1\)
\(x=\frac{4}{3}-\frac{1}{3}\)
\(x=\frac{3}{3}=1\)
\(x+\frac{1}{3}=\frac{4}{3}\)
\(x=\frac{4}{3}-\frac{1}{3}\)
\(x=\frac{3}{3}\)
\(x=1\)
trời ơi bài này mà cũng không làm được hả?
x = 4/3 - 1/3 = 1
\(x+\frac{1}{3}=\frac{4}{3}\)
\(x=\frac{4}{3}-\frac{1}{3}\)
\(x=\frac{3}{3}=1\)
x+\(\frac{1}{3}\)=\(\frac{4}{3}\)
x =\(\frac{3}{3}\)
x =1
\(x+\frac{1}{3}=\frac{4}{3}\)
\(x=\frac{4}{3}-\frac{1}{3}\)
\(x=\frac{3}{3}=1\)
x - \(\frac{1}{3}\)= \(\frac{4}{3}\)
x = \(\frac{4}{3}\)- \(\frac{1}{3}\)
x = 1
k giúp mik nha <3