Question

Tìm X
(X+2)+(X+4)+(X+6)+(X+8)+(X+10)=200

Answer 1

[X+2]+[X+4]+...+[X+10]=200

[X+X+X+....+X]+[2+4+...+10]

5X+[[10+2]*[[10-2]:2+1]]:2

5X+30=200

5X=170

X=170:5

X=34

Answer 2

\(\Leftrightarrow5x+\frac{\left[\left(10-2\right):2+1\right]\left(10+2\right)}{2}=200\)

\(\Leftrightarrow5x+30=200\)

\(\Leftrightarrow5x=270\)

\(\Leftrightarrow x=54\)

Answer 3

(x + 2) + (x + 4) + (x + 6) + (x + 8) + (x + 10) = 200

x + 2 + x + 3 + x + 4 + x + 5 + x + 6 + x + 7 + x + 8 + 10 = 200

5x + 30 = 200

5x = 200 - 30

5x = 170

x = 170 : 5

x = 34

Answer 4

Lê Mai Phương

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