Question

Tìm x

(X+1)+(x+2)+(x+3)+(x+4)+(x+5)=40

Giải giúp mình với

 

Answer 1

( x+ 1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) = 40

x + ( 1 + 2 + 3 + 4 + 5 ) = 40

x + 15 = 40

x = 25

Answer 2

( x+ 1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) = 40

x + ( 1 + 2 + 3 + 4 + 5 ) = 40

x + 15 = 40

x = 25

Answer 3

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) = 40

=> x + ( 1 + 2 + 3 + 4 + 5 ) = 40

=>  x + 15 = 40

=> x = 40 - 15 

=> x = 25

Chúc bn học giỏi ^^

Answer 4

(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=40

x+(1+2+3+4+5)=40

x+15=40

x      =40-15

x       =25

Answer 5

( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) = 40

x + ( 1 + 2 + 3 + 4 + 5 ) = 40

x + 15 = 40

x = 25

Answer 6

Thank you very much!