Question

tìm x

(x+1)^2=9  

giúp tui nha đang cần gấp

 

Answer 1

( x + 1 )² = 9

\(\Rightarrow\orbr{\begin{cases}\left(x+1\right)^2=3^2\\\left(x+1\right)^2=\left(-3\right)^2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x+1=3\\x+1=-3\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=2\\x=-4\end{cases}}\)

Answer 2

(x-1)^2=9  
<=>(x-1)^2 - 3^2 = 0 
<=>(x-1 +3) ( x-1 -3) = 0 
<=> (x+2) .(x-4) = 0 
<=> x= -2 hay x = 4 

Vậy.............

 

Answer 3

 (x+1)^2=3^2   

=> x+1=3 =>x=2

Answer 4

cảm ơn nha