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\(x-\frac{1}{2}=\frac{2}{4}\)
\(x=\frac{2}{4}+\frac{1}{2}\)
\(x=1\)
\(x\) - \(\frac{1}{2}\) = \(\frac{2}{4}\)
\(x\) = \(\frac{2}{4}\) + \(\frac{1}{2}\)
\(x\) = \(\frac{1}{2}\)
Đáp số : \(\frac{1}{2}\)
tìm x:
\(x.\frac{1}{2}=\frac{1}{2}+\frac{2}{4}\)
tìm x:
\(x-\frac{1}{2}=\frac{2}{4}+\frac{1}{2}\)
tìm x:
\(x+\frac{3}{4}=\frac{1}{2}.\frac{2}{3}\)
tìm x biết:
\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
Tìm x:\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)
Trả lời:x là......
Tìm x, biết:
x+\(\frac{1}{2}\)=\(\frac{1}{4}\)+\(\frac{2}{4}\)
*Tìm x:
a,\(X+\frac{1}{2}-\frac{3}{4}=\frac{5}{6}\) b,\(Xx\frac{1}{3}:\frac{2}{5}=\frac{4}{3}\)
Tìm X
\(\frac{1}{4}x\frac{1}{5}xX=\frac{1}{2}\)
tìm x :
\(1\frac{1}{2}-x=\frac{3}{4}\)
