x-2015/2+x-2016/3=x-2017/4+x-2018/5
(x-2015)/2-1+(x-2016)/3-1=(x-2017)/4-1+(x-2018)/5-1
x-2013/2+x-2013/3=x-2013/4+x-2013/5
(x-2013)/2+(x-2013)/3-(x-2013)/4-(x-2013)/5=0
(x-2013)*(1/2+1/3-1/4-1/5)=0
Do 1/2>1/4; 1/3>1/5
\(\Rightarrow\)1/2-1/4+1/3-1/5>0
Vậy x-2013=0
x=-2013