Question

Tìm x

(x + 2) . (3x - 2) - (3x - 1) . (x - 5) = 11

 

Answer 1

\(\left(x+2\right).\left(3x-2\right)-\left(3x-1\right).\left(x-5\right)=11\)

\(\Rightarrow3x^2-2x+6x-4-\left(3x^2-15x-x+5\right)=11\)

\(\Rightarrow3x^2-2x+6x-4-3x^2+15x+x-5=11\)

\(\Rightarrow20x-9=11\)

\(\Rightarrow20x=20\Rightarrow x=1\)

Answer 2

(x + 2)(3x - 2) - (3x - 1)(x - 5) = 11

=> 3x² - 2x + 6x - 4 - 3x² + 15x + x - 5 = 11

=> 20x - 9 = 11

=> 20x = 11 + 9

=> 20x = 20

=> x = 20 : 20

=> x = 1

Answer 3

(x + 2).(3x - 2) - (3x - 1).(x - 5) = 11

--> 3x² - 2x + 6x -4 - 3x² - 15x - x + 5 = 11

--> -12x = 10

--> x = \(\frac{-5}{6}\)

Vậy x = \(\frac{-5}{6}\)

~ Học tốt ~

Answer 4

\(\left(x+2\right).\left(3x-2\right)-\left(3x-1\right).\left(x-5\right)=11\)

\(\Rightarrow3x^2-2x+6x-4-\left(3x^2-15x-x+5\right)=11\)

\(\Rightarrow3x^2-2x+6x-4-3x^2+15x+x-5=11\)

\(\Rightarrow20x-9=11\)

\(\Rightarrow20x=11+9\)

\(\Rightarrow20x=20\)

\(\Rightarrow\)\(x=20:20\)

\(\Rightarrow x=1\)