th1 \(\left(\frac{3}{4}x-5\right)^2=\left(+-\frac{3}{7}\right)^2\)
suy ra 3/4x-5=3/7
3/4x=3/7+5
3/4x=5/3/7
x=5/3/7:3/4
x=7/5/21
th2 3/4x-5=-3/7
3/4x=-3/7+5
3/4x=4/4/7
x=4/4/7:3/4
x=6/2/21
Tìm x, biết :
a, \(60\%x+0,4x+x:3=2\)
b, \(\left|2x-5\right|-7=\left(\frac{1}{49}-\frac{1}{3^2}\right)\left(\frac{1}{49}-\frac{1}{4^2}\right)...\left(\frac{1}{49}-\frac{1}{2015^2}\right)\)
c, \(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+...+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
Tìm x biết :
\(\left[\frac{6:\frac{3}{5}-1\frac{1}{16}.\frac{6}{7}}{4\frac{1}{5}.\frac{10}{11}+5\frac{2}{11}}-\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{15}\right).\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\right].x=2\frac{23}{96}\)
Tìm \(x\) biết:
a)\(\left|2x-5\right|-7=\left(\frac{1}{49}-\frac{1}{3^2}\right)\left(\frac{1}{49}-\frac{1}{4^2}\right).....\left(\frac{1}{49}-\frac{1}{2015^2}\right)\)
b)\(\frac{x+1}{1}+\frac{2x+3}{3}+\frac{3x+5}{5}+...+\frac{20x+39}{39}=22+\frac{4}{3}+\frac{6}{5}+...+\frac{40}{39}\)
Tìm x:
a,\(x:\left(9\frac{1}{2}-\frac{3}{2}\right)=\frac{\frac{2}{5}+\frac{4}{9}-\frac{5}{11}}{\frac{8}{5}+\frac{16}{9}-\frac{20}{11}}\)
b,\(\left|2x-\frac{1}{3}\right|-\left(-2^2\right)=4\left(\frac{1}{-2}\right)^3\)
\(\left(\frac{x}{-5}+1\frac{1}{2}\right):\frac{28}{75}-1,4\cdot\frac{15}{49}=\left|-\frac{2}{3}\right|.\left(-\frac{3}{2}\right)^3\)
Tìm x
a)\(\left(6:\frac{3}{5}-1\frac{1}{6}x\frac{6}{7}\right):\left(4\frac{1}{5}x\frac{10}{11}+5\frac{2}{11}\right)\)
b)\(\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{5}\right)}{3\frac{1}{3}+\frac{2}{9}}\times\frac{12}{49}\)
Bài 1: Thực hiện phép tính
a,\(22\frac{1}{2}.\frac{7}{9}+50\%-1,25\)
b,\(1,4.\frac{15}{49}-\left(\frac{4}{5}+\frac{2}{3}\right):2\frac{1}{5}\)
c,\(\left(\frac{-1}{2}\right)^2-\frac{7}{16}:\frac{7}{4}+75\%\)
Bài 2: Tìm x
a,\(1\frac{3}{5}+\frac{7}{12}:x=\frac{-9}{4}\)
b,\(\left(2\frac{4}{5}.x+50\right):\frac{2}{3}=-51\)
c,\(|\frac{3}{4}.x-\frac{1}{2}|=\frac{1}{4}\)
\(\left(\frac{3}{4}x-5\right)^2=\frac{9}{49}\)
Tìm x:
\(\frac{\left(13\frac{2}{9}-15\frac{2}{3}\right)\cdot\left(30^2-5^4\right)}{\left(18\frac{3}{7}-17\frac{1}{4}\right)\cdot\left(25-12\cdot5^2\right)}\cdot x=\frac{\frac{2}{11}+\frac{3}{13}+\frac{4}{15}+\frac{5}{17}}{4\frac{1}{11}+\frac{5}{13}+\frac{9}{15}+\frac{13}{17}}\)
