Question

Tìm \(x:\)\(\left(2x-6\right)\left(x^2-1\right)-\left(3x-9\right)\left(x+1\right)^2=0\)

Answer 1

\(\left(2x-6\right)\left(x^2-1\right)-\left(3x-9\right)\left(x+1\right)^2=0\)

\(\Leftrightarrow2\left(x-3\right)\left(x^2-1\right)-3\left(x-3\right)\left(x+1\right)^2=0\)

\(\Leftrightarrow\left(x-3\right)\left(2\left(x^2-1\right)-3\left(x+1\right)^2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-3=0\\\left(2\left(x^2-1\right)-3\left(x+1\right)^2\right)=0\end{cases}}\)

tự làm nốt nha

\(\)

\(\)