Question

Tìm X:

\(\frac{X+6}{33}\)= \(\frac{7}{11}\).

Answer 1

cậu làm được không?

Answer 2

\(\frac{x+6}{33}=\frac{7}{11}\)

33 :3=11

x+6:3=7

7 x 3=21

21-6=15

Vậy\(\frac{15+6}{33}=\frac{7}{11}\)

Answer 3

\(X+6=\frac{7.33}{11}\)

\(X+6=21\)

\(X=21-6\)

\(X=5\)

Answer 4

\(\frac{x+6}{33}=\frac{7}{11}\)

\(\Rightarrow\left(x+6\right)\cdot11=33\cdot7\)

( x + 6 ) * 11 = 231

x + 6 = 231 : 11

x + 6 = 21

x = 21 - 6

x = 15

Answer 5

x+6/33= 7/11

=> 7/11= 21/33

Vậy nên x= 21-6= 15.

Answer 6

 Cách giải 1 :

\(\frac{x+6}{33}=\frac{7}{11}\Rightarrow\frac{x+6}{33}=\frac{7.3}{11.3}\Rightarrow\frac{x+6}{33}=\frac{21}{33}\Rightarrow x+6=21\Rightarrow x=15\)

Cách giải 2 :

\(\frac{x+6}{33}=\frac{7}{11}\Rightarrow\left(x+6\right):33=\frac{7}{11}\Rightarrow x+6=\frac{7}{11}.33\Rightarrow x+6=21\Rightarrow x=15\)

Answer 7

ta dổi phân số 7/11 = 21/33 

21 - 6 / 33 = 15/33 

X = 15 

Answer 8

\(\frac{x+6}{33}=\frac{7}{11}\)

\(\frac{\left(x+6\right)\div3}{33\div3}=\frac{7}{11}\)

\(x+6=7\times3=21\)

\(x=21-6=15\)

Answer 9

\(\frac{x+6}{33}=\frac{7}{11}\)

( x + 6 ) . 11 = 33 . 7

( x + 6 ) . 11 = 231

  x + 6          = 231 : 11

  x + 6          = 21

  x                = 21 - 6

  x                = 15

Vậy x = 15