\(\frac{x-1}{9}=\frac{8}{3}\)
Khi (x-1).3=8.9
(x-1).3=72
x-1=72:3
x-1=24
\(\frac{-x}{5}=\frac{5}{x}\)
Khi -x.x=5.5
=>x ko có số nào thỏa mãn đề bài
\(\frac{x}{4}=\frac{18}{x+1}\)
Khi x.(x+1)=18.4
x.(x+1)=72
=>x=8
\(\frac{x-1}{9}=\frac{8}{3}\)
Khi (x-1).3=8.9
(x-1).3=72
x-1=72:3
x-1=24
\(\frac{-x}{5}=\frac{5}{x}\)
Khi -x.x=5.5
=>x ko có số nào thỏa mãn đề bài
\(\frac{x}{4}=\frac{18}{x+1}\)
Khi x.(x+1)=18.4
x.(x+1)=72
=>x=8
1) \(\frac{24}{-12}=\frac{x}{5}=\frac{-y}{3}\)Tìm x và y
2) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-5}{25}\le\frac{x}{10}< \frac{-3}{4}+\frac{4}{14}+\frac{-2}{8}+\frac{-3}{5}+\frac{5}{7}\)Tìm x
3) \(\frac{8.x+18}{2.x+6}\)Tìm x
\(\frac{5}{8}-\frac{x}{3}=\frac{-1}{8}\)
\(\frac{7}{9}-\frac{4}{x}=\frac{5}{18}\)Tim x .
tìm x biết
1, \(x\cdot\frac{6}{25}=\frac{15}{-13}\)
2, \(x\div\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\)
3, \(\frac{3}{8}-\frac{1}{6}\cdot x=\frac{1}{4}\)
4, \(\frac{1}{3}+\frac{1}{2}\div x=-4\)
5, \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
tìm x biết
1, \(x\cdot\frac{6}{25}=\frac{15}{-13}\)
2, \(x\div\frac{4}{10}=\frac{13}{-45}+\frac{8}{15}\)
3, \(\frac{3}{8}-\frac{1}{6}\cdot x=\frac{1}{4}\)
4, \(\frac{1}{3}+\frac{1}{2}\div x=-4\)
5, \(x+\frac{7}{12}=\frac{17}{18}-\frac{1}{9}\)
bài 15 tìm x biết
a\(\frac{x}{4}-\frac{3}{7}+\frac{2}{5}=\frac{31}{140}\)
b\(\frac{5}{12}+\frac{5}{x}-\frac{1}{8}=\frac{1}{2}\)
c\(x+\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
d\(\frac{3}{4}-x+\frac{6}{-11}=\frac{5}{6}\)
e\(x-\frac{1}{9}-\frac{3}{5}=\frac{3}{6}\)
Tìm x
a)\(\frac{1}{3}+\frac{3}{35}< \frac{x}{210}< \frac{4}{7}+\frac{3}{5}+\frac{1}{3}\)
b)\(\frac{5}{3}+\frac{-14}{3}< x< \frac{8}{5}+\frac{18}{10}\)
c)\(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}< x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
bài 1 : tìm x biết
a, \(\frac{2}{3}\times\left(x-\frac{5}{6}\right)+\frac{1}{4}=\frac{22}{9}\)
b, \(\frac{2}{3}:\frac{x}{5}=\frac{10}{21}\)
c, \(\frac{7}{3}:\frac{x}{5}=\frac{14}{15}\)
d, \(1-\left(5\frac{4}{9}\times x-7\frac{7}{18}\right):15\frac{3}{4}=0\)
bài 2 : tính gtri bt
a,\(\frac{8}{7}+\frac{1}{5}\times\frac{10}{9}\)
b, \(\frac{3}{2}+\left(\frac{9}{2}+\frac{2}{9}\right)\times\left(\frac{4}{3}-\frac{5}{4}\right)\)
!_ove
Bài 1: Tìm x
a. \(x-\frac{5}{12}-\frac{4}{9}=\frac{-13}{18}\)
b. \(2-\left(x+\frac{3}{7}\right)=\frac{9}{-21}\)
c. \(x-\frac{-3}{11}=\frac{6}{22}+\frac{1}{4}\)
d. \(\frac{13}{36}-\frac{5}{18}-x=\frac{-11}{9}\)
e. \(x-\frac{3}{7}:\frac{9}{14}=\frac{-17}{3}\)
f. \(\left(x-\frac{1}{2}\right):\frac{3}{11}=\frac{11}{4}\)
g. \(\left(2x+\frac{3}{8}\right).\frac{7}{4}=-\frac{21}{32}\)
h. \(x-\frac{x}{3}=\frac{3}{57}:\frac{12}{19}\)
Vì dài qua cho nên bài 2 mình để riêng nhé
tìm x biết
1, \(x-\frac{3}{5}=\frac{3}{35}-\frac{-7}{6}\)
2, \(\frac{x}{120}=\frac{3}{8}\cdot\frac{-4}{25}\)
3, \(\frac{11}{13}\cdot x=1\)
4, \(-\frac{9}{8}+\frac{-3}{8}\cdot x=\frac{-1}{8}\)
5, \(\frac{-2}{5}\cdot x+\frac{4}{3}=\frac{7}{3}\)