\(\frac{x-1}{2015}-\frac{1}{2015}=\frac{10-2x}{2015}\)
\(\Rightarrow x-1-1=10-2x\)
\(\Rightarrow x-2=10-2x\)
\(\Rightarrow-2x+x=10+2\)
\(\Rightarrow-x=12\Rightarrow x=-12\)
\(\frac{x-1}{2015}-\frac{1}{2015}=\frac{10-2x}{2015}\)
\(\Rightarrow x-1-1=10-2x\)
\(\Rightarrow x-2=10-2x\)
\(\Rightarrow-2x+x=10+2\)
\(\Rightarrow-x=12\Rightarrow x=-12\)
Giá trị x thỏa mãn:
\(\frac{x-4}{2015}-\frac{1}{2015}=\frac{10-2x}{2015}\)
\(\frac{x-4}{2015}-\frac{1}{2015}=\frac{10-2x}{2015}\)
Giai nhanh giup to!
Giá trị x thỏa mãn : \(\frac{x-4}{2015}\)-\(\frac{1}{2015}\)=\(\frac{10-2x}{2015}\)
Giá trị của x thỏa mãn: \(\frac{x-4}{2015}\)-\(\frac{1}{2015}\)=\(\frac{10-2x}{2015}\)
Tim x
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
2/ tim x
\(\frac{x+2015}{5}+\frac{x+2016}{6}=\frac{x+2017}{7} +\frac{x+2018}{8}\)
3/ tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{99}{101}+\frac{1}{15}+... +\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)
Tìm x
1) \(\frac{-7}{4}x\cdot\left(\frac{33}{12}+\frac{3333}{2020}+\frac{333333}{303030}+\frac{33333333}{42424242}\right)=22\)
2) \(\frac{1}{2016}:2015\cdot x=\frac{-1}{2015}\)
\(\frac{x+1}{2015}=\frac{2015}{x+1}\)
Cho biết \(\frac{x+2015}{x-2015}=\frac{y+2017}{y-2017}\) (x khác 2015 và -2015: y khác 2017 và -2017)
Tìm \(\frac{x}{y}\)
Tính tổng gồm 2014 số hạng:
\(f\left(\frac{1}{2015}\right)+f\left(\frac{2}{2015}\right)+....+f\left(\frac{2014}{2015}\right)\)
Trong đó \(f\left(x\right)=\frac{100^x}{100^x+10}\)
ai làm đg tick nha