Question

Tìm X:\(\frac{2.\left(x-5\right)}{-9}\)=\(\frac{6}{\left(x-5\right)^2}\).(-1)

Giúp mk nha đag cần gấp.Cảm ơn

Answer 1

\(\frac{2.\left(x-5\right)}{-9}=\frac{6}{\left(x-5\right)^2}.\left(-1\right)\)

\(\frac{2.\left(x-5\right)}{-9}=\frac{-6}{\left(x-5\right)^2}\)

\(2.\left(x-5\right).\left(x-5\right)^2=\left(-9\right).\left(-6\right)\)(nhân chéo)

\(2.\left(x-5\right).\left(x-5\right)^2=54\)

\(\left(x-5\right).\left(x-5\right)^2=54:2=27\)

\(\Rightarrow27⋮x-5\)

\(x-5\inƯ\left(27\right)\)

\(x-5\in\left\{-27;-9;-3;-1;1;3;9;27\right\}\)

\(x\in\left\{-22;-4;2;4;6;8;14;32\right\}\)