Question

Tìm x

\(\frac{1}{3}\). x - 0,5 . x = 0,75

Answer 1

\(\frac{1}{3}x-0,5x=0,75\)

\(\Rightarrow-\frac{1}{6}x=0,75\)

\(\Rightarrow x=-\frac{9}{2}\)

Answer 2

\(\frac{1}{3}x-\frac{1}{2}x=\frac{3}{4}\)

\(\left(\frac{1}{3}+\frac{1}{2}\right)x=\frac{3}{4}\)

\(\frac{5}{6}x=\frac{3}{4}\)

\(x=\frac{3}{4}\div\frac{5}{6}\)

\(x=\frac{3}{4}\cdot\frac{6}{5}=\frac{9}{10}\)

                           \(#Cothanhkhe\)

Answer 3

\(\frac{1}{3}.x-0,5.x=0,75\)

\(\frac{1}{3}.x-\frac{1}{2}.x=\frac{3}{4}\)

\(x.\left(\frac{1}{3}-\frac{1}{2}\right)=\frac{3}{4}\)

\(x.\left(\frac{2}{6}-\frac{3}{6}\right)=\frac{3}{4}\)

\(x.\frac{-1}{6}=\frac{3}{4}\)

\(x=\frac{3}{4}:\frac{-1}{6}\)

\(x=\frac{-9}{2}\)

Answer 4

\(x\left(\frac{1}{3}-\frac{1}{2}\right)=\frac{3}{4}\)

=>\(x=\frac{3}{4}:\left(\frac{-1}{6}\right)=\frac{3}{4}.\left(-6\right)=\frac{-9}{2}\)