Question

TÌM xEQ biết

a) |x^2 - 3x|=0

b) |4x - 4|=4x-4

c) |2x - 3|=3x - 2

d) |5x - 1|=|3 - 2x|

e) x+1| + |x-3|=3

Ai bít thì giúp vs ^^!

Answer 1

a, |x^2 - 3x| = 0

=> x^2 - 3x = 0

=> x(x - 3) = 0

=> x = 0 hoặc x - 3 = 0 

=> x = 0 hoặc x = 3

vậy_

Answer 2

\(\left|a^2-3a\right|=0\)

\(\Rightarrow a^2-3a=0\)

\(\Rightarrow a\left(a-3\right)=0\)

\(\Rightarrow\hept{\begin{cases}a=0\\a=3\end{cases}}\)

Answer 3

Trả lời

Vì lx²-3xl=0

Nên x²-3x=0

=>x(x-3)=0

x=0.           x-3=0

                    x=3

Học tốt

Answer 4

\(\left|4a-4\right|\ge0\)

\(\Rightarrow4a-4\ge0\)

\(\Rightarrow4a\ge4\)

\(\Rightarrow a\ge1\)

Answer 5

\(\left|2a-3\right|=3a-2\)

\(\Rightarrow2a-3=\hept{\begin{cases}3a-2\\2-3a\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}3a-2a=-3+2\\2a+3a=2+3\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}a=-1\\5a=5\end{cases}}\)

\(\Rightarrow\hept{\begin{cases}a=-1\\a=1\end{cases}}\)