Question

Tìm x,biết:

\(\frac{x+1}{2}=\frac{x-2}{3}\)

Các bn giúp mk nha.Cảm ơn nhìu

Answer 1

\(\frac{x+1}{2}=\frac{x-2}{3}\)

\(\Rightarrow\left(x+1\right).3=\left(x-2\right).2\)

\(3x+3=2x-4\)

\(\Rightarrow3x-2x=-4-3\)

\(x=-7\)

KL: x= -7

Học tốt nhé bn !!

Answer 2

\(\frac{x+1}{2}=\frac{x-2}{3}\)

=> (x+1).3 = 2(x-2)

=> 3x + 3 = 2x - 2

=> 3 + 2 = 2x - 3x

=> 5 = -x

=> x = -5

Answer 3

\(\frac{x+1}{2}=\frac{x-2}{3}\)

\(\Rightarrow\left(x+1\right)3=2\left(x-2\right)\)

\(\Rightarrow3x+3=2x-4\)

\(\Rightarrow3x-2x=-4-3\)

\(\Rightarrow x=-7\)

vậy \(x=-7\)