5x(1-2x)-3x(x+18)=0
=> \(5x-10x^2-3x^2-54x=0\)
=> \(-49x-13x^2=0\)
=> \(x\left(-49-13x\right)=0\)
Suy ra
\(x=0\)\(-49-13x=0\)=> \(-13x=49\)=> \(x=\frac{-49}{13}\)Vậy \(x=\frac{-49}{13}; x=0\)
tìm x biết
1. 5x( 1 - 2x ) - 3x( x + 18 ) = 0
2. (12x - 5)* (4x - 1) + ( 3x - 7) * ( 1 - 16x ) = 81
tìm x : 5x(1-2x) - 3x ( x+18) =0
Tìm x biết:
5x(1 - 2x) - 3x(x +18) = 0 (có 2 giá trị x thỏa mãn)
Tìm x
5x.(1-2x)-3x.(x+18)=0
Tìm x 5x-(1-2x)-3x(x+18)=0
tìm x
a)5x ( 1 - 2x ) - 3x ( x + 18 ) = 0
b)5x - 10x^2 - 3x^2 - 54 = 0
Tìm x
5x( 1 - 2x ) - 3x( x + 18) = 0
Tìm x biết :
a) 2( 5x- 8) - 3( 4x- 5) = 4(3x- 4) + 11
b) 3x(x+ 1) - 2x(x+ 2) = -x -1
c) 5x(1- 2x) - 3x( x+ 18) = 0
tìm x biết
a) (6x-3) (2x+4) + (4x-1) (5-3x) = -21
b) 6x (3x+5) - 2x (9x-2) + (17-x) (x-1) + x (x-18) =0
c) (15-2x) (4x+1) - (13-4x) (2x-3) - (x-1) (x+2) + x2=52
d) (8x-3) (3x+2) - (4x+7) (x+4) = (2x+1) (5x-1) - 33
