\(2^{3x+2}=4^{x+5}\)
\(\Rightarrow2^{3x+2}=\left(2^2\right)^{x+5}\)
\(\Rightarrow2^{3x+2}=2^{2\left(x+5\right)}\)
=> 3x+2=2(x+5)
=> 3x+2=2x+10
=> 3x-2x+2-10=0
=> x-8=0
=> x=0+8
=> x=8
4x+5 = 22(x+5)=22x+10
= > 3x + 2 = 2x + 10
= > 3x - 2x = 10 - 2
= > x = 8
làm như lê ánh tú ấy
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