\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{5}{6}+x-x+\frac{2}{3}\)\(=0\)
\(\Leftrightarrow x-\frac{1}{6}=0\)
\(\Leftrightarrow x=\frac{1}{6}\)
\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{5}{6}+x=x-\frac{2}{3}\)
\(\Leftrightarrow x+x-x=\frac{5}{6}-\frac{2}{3}\)
\(\Leftrightarrow x=\frac{1}{6}\)
Vậy ..........
\(x-\left(\frac{5}{6}-x\right)=x-\frac{2}{3}\)
\(\Leftrightarrow x-\frac{5}{6}+x=x-\frac{2}{3}\)
\(\Leftrightarrow x+x-x=\frac{5}{6}-\frac{2}{3}\)
\(\Leftrightarrow x=\frac{1}{6}\)