Question

Tìm x,biết : (-2x)*(x+3)+x*(2x-10)=10

Answer 1

`(-2x) xx (x+3) + x xx ( 2x-10) =  10`

`<=> -2x^2 - 6x + 2x^2 - 10x = 10`

` => -6x -10x = 10`

`=> -16x = 10`

` => x =10:(-16)`

` => x = -5/8`

 

Answer 2

\(\Leftrightarrow-2x^2-6x+2x^2-10x=10\)

=>-16x=10

hay x=-5/8

Answer 3

(−2x)×(x+3)+x×(2x−10)= 10(-2x)×(x+3)+x×(2x-10)= 10

 

⇔−2x2−6x+2x2−10x=10⇔-2x2-6x+2x2-10x=10

 

⇒−6x−10x=10⇒-6x-10x=10

 

⇒−16x=10⇒-16x=10

 

⇒x=10:(−16)⇒x=10:(-16)

 

⇒x= - 5/8.