a) Nếu \(\frac{1}{2}x\ge0\Rightarrow x\ge0\) thì \(\left|\frac{1}{2}x\right|=3-2x\Rightarrow\frac{1}{2}x=3-2x\Rightarrow\frac{5}{2}x=3\Rightarrow x=\frac{6}{5}\) (nhận)
Nếu \(\frac{1}{2}x< 0\Rightarrow x< 0\) thì \(\left|\frac{1}{2}x\right|=3-2x\Rightarrow-\frac{1}{2}x=3-2x\Rightarrow\frac{3}{2}x=3\Rightarrow x=2\) (loại)
Vậy x = 6/5
b) Nếu \(x-1\ge0\Rightarrow x\ge1\) thì \(\left|x-1\right|=3x+2\Rightarrow x-1=3x+2\Rightarrow-2x=3\Rightarrow x=\frac{-2}{3}\) (loại)
Nếu \(x-1< 0\Rightarrow x< 1\) thì \(\left|x-1\right|=3x+2\Rightarrow-\left(x-1\right)=3x+2\Rightarrow-x+1=3x+2\Rightarrow-4x=1\Rightarrow x=\frac{-1}{4}\) (nhận)
Vậy x = -1/4
