Question

Tìm x:

a)2(3x-2)-3(x-2)=-1

b)3(3-2x^2)+3x(2x-1)=9

c)4x^2 (x-x^2)-4x(-x^3+x^2-5)=20

d)2x(x-5)-x(3+2x)=26

Answer 1

\(a,6x-4-3x+6=-1\\ 3x+2=-1\\ 3x=-1-2\\ 3x=-3\\ x=-1\\ b,9-6x^2+6x^2-3x=9\\ 9-3x=9\\ 3x=0\\ x=0\\ c,4x^3-4x^4+4x^4-4x^3+20x=20\\ 20x=20\\x=1\\ d,2x^2-10x-3x-2x^2=26\\ -13x=26\\ x=26:\left(-13\right)\\ x=-2 \)

Answer 2

`a)2(3x-2)-3(x-2)=-1`

`<=> 6x - 4 - 3x +6 +1 =0`

`<=> 3x +3=0`

`<=> 3x = -3`

`=> x = -3/3 =-1`

`b)3(3-2x^2)+3x(2x-1)=9`

`<=> 9 - 6x^2 + 6x^2 - 3x -9=0`

`<=> -3x =0`

`=> x=0`

Answer 3

a, \(6x-4-3x+6=-1\Leftrightarrow3x+3=0\Leftrightarrow x=-1\)

b, \(9-6x^2+6x^2-3x=9\Leftrightarrow-3x=0\Leftrightarrow x=0\)

c, \(4x^3-4x^4+4x^4-4x^3+20x=20\Leftrightarrow x=1\)

d, \(2x^2-10x-3x-2x^2=26\Leftrightarrow-13x=26\Leftrightarrow x=-2\)

Answer 4

`c)4x^2 (x-x^2)-4x(-x^3+x^2-5)=20`

`<=> 4x^3 -4x^4 + 4x^4 - 4x^3 +20x -20=0`

`<=> 20x-20=0`

`<=> 20(x-1)=0`

`=> x-1=0`

`=> x=1`

`d)2x(x-5)-x(3+2x)=26`

`<=> 2x^2 - 10x - 3x -2x^2 -26=0`

`<=> -13x =26`

`<=> x=26/-13 =-2`